Consider the function defined for 0 < x < 1
f(x)1 if 10 n < x < 10 n and n is an even positive integer = if 10 n < x < 10 n and n is an odd positive integer. (a) What it the value f(x) for x = 0.9, x = 0.05, and x = 0.003? (b) For every e > 0 and every 5 > 0 there exists an 0 < x < 5 so that 11(x) — 11 < a (c) Prove that the statement lira f(x) = 1 is false. You may only use the precise definition of a limit (e-5 definition). You are not allowed to use
limit laws.