Mathematics question
Determine Mathematics the values of m and n for π(π₯) = ππ₯^3 + 12π₯^2 + ππ₯ β 3 given that the remainder when dividing by (π₯ + 3) is zero, and when divided by (π₯ β 2) the remainder is 85.
85 = m(2)^3 + 12(2)^2 + n(2) -3
85 = 8m +48 +2n -3
85-48+3 = 8m+2n
40/2 = 8m +2n /2
20 = 4m + n (Equation 1)
0 = m(-3)^3 +12(-3)^2 +n(-3) -3
0 = -27m +108 -3n -3
0 = -27m +105 -3n
-105/-3 = -27m -3n /-3
35 = 9m + n (equation 2)
(equation 1 – equation 2) 20 = 4m + n – 35 = 9m + n —> -15 = 5m divide by 5 and you get m = -3
now plug m into equation 1 to get n
20 = 4(-3) + n —> n= 32